\bullet\begin{cases} 2x+3y=7\\ 5x-y=9\end{cases}
\begin{cases} 2x+3y=7\\ y=5x-9\end{cases}
2x+3\left( 5x-9\right) =7
2x+15x=7+27
\boxed{x=2}
Sustituimos
2\cdot2+3y=7
\boxed{y=1}
\bullet\begin{cases} x-2y=5\\ 2x-3y=9\end{cases}
\begin{cases} x=5+2y\\ 2x-3y=9\end{cases}
2\left( 5+2y\right) -3y=9
10+4y-2y=9
\boxed{y=-1}
Sustituimos
x=5-2\cdot1
\boxed{x=3}
\bullet \begin{cases} 2x+y=7\\ 5x-3y=1\end{cases}
\begin{cases} y=7-2x \\ 5x-3y=1\end{cases}
5x-3\left( 7-2x\right) =1
\boxed{x=2}
Sustituimos
y=7-2\cdot2
\boxed{y=3}
\bullet\begin{cases} 5x-2y=5\\ 2x-3y=-9\end{cases}
\begin{cases} x=\dfrac {3y-9} {2}\\ 5x-2y=5\end{cases}
5\left( \dfrac {3y-9} {2}\right) -2y=5
\dfrac {15y-45} {2}-2y=5
15y-45-4y=10
\boxed{y=5}
Sustituimos
x=\dfrac {15-9} {2}
\boxed{x=3}
\bullet \begin{cases} 2x+5y=-2\\ 3x-2y=16\end{cases}
\begin{cases} x=\dfrac {-2-5y} {2}\\ 3x-2y=16\end{cases}
3\left( \dfrac {-2-5y} {2}\right) 2y=16
\dfrac {-6-15y} {2}-2y=16
-6-15y-4y=32
\boxed{y=-2}
Sustituimos
x=\dfrac {-2+5\cdot2} {2}
\boxed{x=4}
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