Valor númerico 2

En estos ejercicios tenemos que sustituir el valor de la variable y realizar las operaciones.

$\bullet P\left( x\right) =3x^{2}-5x+3;\ \ x=2$

$P\left( 2\right) =3\cdot 2^{2}-5\cdot 2+3$

$P\left( 2\right) =12-10+3$

$\boxed{P\left( 2\right) = 5}$

$\bullet P\left( x,y\right) =2x^{3}y-5x;\ \ x=-1\ \ y=5$

$P\left( -1,5\right) =2\cdot 5\left( -1\right) ^{3}-5\left( -1\right)$

$P\left( -1,5\right) =-10+5$

$\boxed{P\left( -1,5\right) =-5}$

$\bullet P\left( x,y\right) =3xy^{3}-2x^{2}y^{2}-1;\ \ x=2\ \ y=-1$

$P\left(2,-1\right) =3-2\left( -1\right) ^{3}-2\cdot 2^{2}\left( -1\right) ^{2}-1$

$P\left(2,-1\right) =-6-8-1$

$\boxed{P\left(2,-1\right) =-15}$

$\bullet P\left( x\right) =\left( \dfrac {x^{2}+x-12} {x+4}\right) ;\ \ x=3$

$P\left( 3\right) =\dfrac {3^{2}+3-12} {3+4}=\dfrac {12-12} {7}$

$\boxed{P\left(3\right) =0}$

$\bullet P\left( a,b\right) =5ab-6+2b^{5};\ \ a=3\ \ b=-2$

$P\left( 3,-2\right) =5\cdot 3\left( -2\right) -6+2\left( -2\right) ^{5}$

$P\left( 3,-2\right) =-30-6-64$

$\boxed{P\left( 3,-2\right) =-100}$